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A hypothetical upper bound on the heights of the solutions of a Diophantine equation with a finite number of solutions

机译:关于a的解的高度的假设上界   具有有限数解的丢番图方程

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摘要

Let f(1)=1, and let f(n+1)=2^{2^{f(n)}} for every positive integer n. Weconjecture that if a system S \subseteq {x_i \cdot x_j=x_k: i,j,k \in{1,...,n}} \cup {x_i+1=x_k: i,k \in {1,...,n}} has only finitely many solutionsin non-negative integers x_1,...,x_n, then each such solution (x_1,...,x_n)satisfies x_1,...,x_n \leq f(2n). We prove: (1) the conjecture implies thatthere exists an algorithm which takes as input a Diophantine equation, returnsan integer, and this integer is greater than the heights of integer(non-negative integer, positive integer, rational) solutions, if the solutionset is finite, (2) the conjecture implies that the question whether or not aDiophantine equation has only finitely many rational solutions is decidablewith an oracle for deciding whether or not a Diophantine equation has arational solution, (3) the conjecture implies that the question whether or nota Diophantine equation has only finitely many integer solutions is decidablewith an oracle for deciding whether or not a Diophantine equation has aninteger solution, (4) the conjecture implies that if a set M \subseteq N has afinite-fold Diophantine representation, then M is computable.
机译:令f(1)= 1,并让f(n + 1)= 2 ^ {2 ^ {f(n)}}对于每个正整数n。我们推测,如果系统S \ subseteq {x_i \ cdot x_j = x_k:i,j,k \ in {1,...,n}} \ cup {x_i + 1 = x_k:i,k \ in {1, ...,n}}仅具有非负整数x_1,...,x_n的有限解,然后每个这样的解(x_1,...,x_n)都满足x_1,...,x_n \ leq f(2n )。我们证明:(1)该猜想意味着存在一种算法,该算法以Diophantine方程为输入,返回整数,并且该整数大于整数(非负整数,正整数,有理数)解的高度(如果解集为高)是有限的,(2)该猜想暗示一个Diophantine方程是否仅具有有限多个有理解的问题可通过一个oracle来确定,以决定一个丢丢丁方程是否具有理性的解,(3)该猜想意味着该问题是否为nota Diophantine方程只有有限的整数解是可确定的,用oracle来确定Diophantine方程是否具有整数解,(4)该猜想意味着,如果集合M \ subseteq N具有无限倍的Diophantine表示,则M是可计算的。

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    Tyszka, Apoloniusz;

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